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Engineering entrance · National Testing Agency (NTA)

JEE Main Mock Tests, Syllabus & Complete Exam Guide

Joint Entrance Examination (Main). Practise 35 full-length mock tests on the official pattern, drill every topic, and get the eligibility, syllabus, cut-off, rank and college details you need — all in one place.

JEE Main at a glance

Questions
75
Total marks
300
Duration
3 hours
Marking
+4 / −1
ModeComputer-based test (online)
FrequencyTwice a year (Session 1 & Session 2)
Languages13 languages
By the ExamguruX Editorial TeamReviewed for pattern accuracy against National Testing Agency (NTA)Last updated 15 July 2026

JEE Main full-length mock tests

Attempt 35 full-length JEE Main mock tests built on the official 75-question, 300-mark pattern. The first few are free — every test comes with instant results and a step-by-step solution for each question.

JEE Main Full Mock Test 01

Free
75 Qs · 300 marks180 min8.4K attemptsModerate
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JEE Main Full Mock Test 02

Free
75 Qs · 300 marks180 min11.8K attemptsHard
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JEE Main Full Mock Test 03

Free
75 Qs · 300 marks180 min15.2K attemptsEasy
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JEE Main Full Mock Test 04

75 Qs · 300 marks180 min18.6K attemptsHard
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JEE Main Full Mock Test 05

75 Qs · 300 marks180 min22.0K attemptsEasy
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JEE Main Full Mock Test 06

75 Qs · 300 marks180 min25.3K attemptsModerate
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JEE Main Full Mock Test 07

75 Qs · 300 marks180 min28.7K attemptsHard
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JEE Main Full Mock Test 08

75 Qs · 300 marks180 min32.1K attemptsModerate
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JEE Main Full Mock Test 09

75 Qs · 300 marks180 min35.5K attemptsHard
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Unlock all JEE Main tests

The first tests in each section are free to try. Get the complete JEE Main mock library, every topic test and all available languages for 3 months — a one-time ₹199 / 3 months.

JEE Main — full access

199/ 3 months
  • Every full-length mock test
  • All topic-wise tests, every subject
  • All available languages
  • Step-by-step solution for every question
  • Indicative marks-to-rank & cut-offs

Secure payment by Razorpay · one-time ₹199 for 3 months

JEE Main topic-wise tests & syllabus

495 topic tests across 3 subjects — a focused set of 15 tests for every topic in the JEE Main syllabus, tagged with approximate exam weightage so you practise where the marks are.

495 topic-wise tests · 15 per topic across 3 subjects. Pick a subject, expand a topic, and start drilling.

Units, Dimensions & Error Analysis — Test 01

Free
15 Qs · 60 marks15 min66.0K attemptsModerate
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Units, Dimensions & Error Analysis — Test 02

Free
15 Qs · 60 marks15 min83.0K attemptsEasy
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Units, Dimensions & Error Analysis — Test 03

25 Qs · 100 marks25 min99.9K attemptsHard
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Units, Dimensions & Error Analysis — Test 04

15 Qs · 60 marks15 min117K attemptsModerate
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Units, Dimensions & Error Analysis — Test 05

15 Qs · 60 marks15 min134K attemptsEasy
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Units, Dimensions & Error Analysis — Test 06

25 Qs · 100 marks25 min151K attemptsHard
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Units, Dimensions & Error Analysis — Test 07

15 Qs · 60 marks15 min168K attemptsModerate
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Units, Dimensions & Error Analysis — Test 08

15 Qs · 60 marks15 min185K attemptsEasy
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Units, Dimensions & Error Analysis — Test 09

25 Qs · 100 marks25 min202K attemptsHard
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Units, Dimensions & Error Analysis — Test 10

15 Qs · 60 marks15 min8.6K attemptsModerate
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Units, Dimensions & Error Analysis — Test 11

15 Qs · 60 marks15 min25.6K attemptsEasy
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Units, Dimensions & Error Analysis — Test 12

25 Qs · 100 marks25 min42.5K attemptsHard
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Units, Dimensions & Error Analysis — Test 13

15 Qs · 60 marks15 min59.5K attemptsModerate
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Units, Dimensions & Error Analysis — Test 14

15 Qs · 60 marks15 min76.5K attemptsEasy
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Units, Dimensions & Error Analysis — Test 15

25 Qs · 100 marks25 min93.4K attemptsHard
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JEE Main sample questions

A few real JEE Main questions with answers and step-by-step solutions, in the exact style of the full mock tests.

PhysicsSample 1

The dimensional formula of Planck's constant is:

  • A.[M L² T⁻¹]
  • B.[M L T⁻¹]
  • C.[M L² T⁻²]
  • D.[M T⁻¹]

Solution: Planck's constant h has units of energy × time (J·s) = [M L² T⁻²][T] = [M L² T⁻¹] — the same dimensions as angular momentum.

ChemistrySample 2

The number of moles present in 36 g of water (H₂O) is:

Solution: Moles = mass / molar mass = 36 / 18 = 2 mol.

MathematicsSample 3

The value of 5! (5 factorial) is:

Solution: 5! = 5 × 4 × 3 × 2 × 1 = 120.

About the JEE Main exam

Admission to B.E./B.Tech at NITs, IIITs and GFTIs, and the qualifying stage for JEE Advanced (IITs).

What is JEE Main?

JEE Main is India's national-level engineering entrance examination, conducted by the National Testing Agency. Paper 1 (B.E./B.Tech) tests Physics, Chemistry and Mathematics through a computer-based test, and a JEE Main rank is used for admission to the 31 NITs, the IIITs and the Government Funded Technical Institutes, as well as by many state and private engineering colleges.

JEE Main is also the qualifying gate for JEE Advanced: the roughly top 2.5 lakh rankers become eligible to attempt JEE Advanced, the exclusive entrance to the IITs. It is held in two sessions each year, and the better of a candidate's two NTA scores is used to compile the final merit list.

Why the two-session, percentile system matters

Because JEE Main runs across many shifts and two sessions, raw marks from different shifts are not directly comparable. NTA converts every candidate's marks into a normalised percentile score, and the All India Rank is drawn from these percentiles — so a 99 percentile means you scored better than 99% of test-takers, not that you scored 99 marks.

The two-session format is a genuine strategic advantage: you can attempt Session 1, learn from a real exam, and improve in Session 2, with only your best score counting. Practising full-length computer-based mocks that mirror the on-screen interface, numerical-answer input and per-section timing is the most reliable way to convert preparation into percentile.

JEE Main eligibility & exam pattern

Check whether you meet the JEE Main eligibility criteria and understand exactly how the paper is structured and marked before you plan your preparation.

Eligibility criteria

Qualifying exam
Class 12 (10+2) or equivalent with Physics and Mathematics as compulsory subjects, plus one of Chemistry, Biology, Biotechnology or a technical vocational subject.
Year of passing
Candidates who passed in the previous two years or are appearing in the current year are eligible.
Age limit
There is no age limit to appear for JEE Main.
Marks for NIT/IIIT admission
For admission you must score at least 75% in Class 12 (65% for SC/ST) or be in the top 20 percentile of your board.
Number of attempts
You may attempt JEE Main in three consecutive years; both sessions in a year count as one attempt.
Nationality
Indian nationals, NRIs, OCIs, PIOs and foreign nationals are eligible.

Exam pattern & marking

SubjectQuestionsMarks
Physics20 MCQ + 5 of 10 numerical25100
Chemistry20 MCQ + 5 of 10 numerical25100
Mathematics20 MCQ + 5 of 10 numerical25100
Total75300

Both MCQs and numerical-value questions carry +4 for a correct answer and −1 for an incorrect one. Unattempted questions are not penalised. In each subject 90 questions are shown; you answer all 20 MCQs and any 5 of the 10 numerical questions (75 in all).

Duration: 3 hours (180 minutes).

How to prepare for JEE Main

A proven, focused JEE Main preparation method — from building strong fundamentals to peaking with full-length mocks.

  1. 1

    Build concepts you can apply, not memorise

    JEE Main rewards application over recall. Derive results, understand where each formula comes from, and solve varied problems on a concept before moving on — rote learning breaks down against JEE's twist questions.

  2. 2

    Make Mathematics your speed engine

    Maths is the most scoring and time-sensitive section. Drill Calculus, Coordinate Geometry and Algebra until you can solve standard problems quickly, freeing time for tougher Physics and Chemistry.

  3. 3

    Practise numerical-value questions deliberately

    The numerical section now carries negative marking too. Practise entering exact values, rounding correctly, and avoiding calculation slips — these questions are where careful students gain a clear edge.

  4. 4

    Master previous-year JEE Main papers

    Concepts repeat across years. Solve at least the last ten years of JEE Main papers, topic-wise first and then as timed sets, to internalise the exact style and difficulty NTA sets.

  5. 5

    Simulate the computer-based test

    Take full 3-hour mocks on screen, with the real question palette and on-screen calculator-free numerical input, so exam day feels familiar and your pacing across three sections is already rehearsed.

  6. 6

    Plan a two-session strategy

    Treat Session 1 as a high-stakes rehearsal, analyse every mistake, and target a higher percentile in Session 2. Because only your best score counts, there is no downside to attempting both.

JEE Main marks vs rank & cut-offs

Your JEE Main All India Rank — not just your marks — decides your college. Use this recent-cycle marks-to-rank map and the official category-wise qualifying cut-offs to set a realistic target score.

JEE Main marks vs. rank

Score rangePercentileExpected AIR
281–30099.99+1 – 300
251–28099.9+300 – 1,400
221–25099.5+1,400 – 7,000
191–22099.0+7,000 – 14,000
161–19098+14,000 – 28,000
131–16096+28,000 – 56,000
101–13090+56,000 – 1,40,000
70–10080+1,40,000 – 2,80,000

Qualifying cut-offs by category

General (CRL)93.41 %ile

Indicative marks: JEE Advanced 2026 cut-off

EWS82.42 %ile

Indicative marks: JEE Advanced 2026 cut-off

OBC-NCL80.92 %ile

Indicative marks: JEE Advanced 2026 cut-off

SC63.92 %ile

Indicative marks: JEE Advanced 2026 cut-off

ST52.02 %ile

Indicative marks: JEE Advanced 2026 cut-off

JEE Advanced qualifying percentiles and dates are from the official JEE Main 2026 cycle (NTA, declared 20 April 2026). Marks-vs-percentile figures follow the published 2025/2026 analysis, and college closing ranks are Computer Science (General, CRL) ranks from JoSAA 2024 — other branches and rounds close at higher ranks. Verify current-year specifics on jeemain.nta.nic.in and josaa.nic.in.

Colleges that accept JEE Main

A JEE Main rank opens admission to the NITs, IIITs and GFTIs through JoSAA/CSAB counselling, plus many state and private institutes. The figures below are Computer Science (General, CRL) closing ranks from JoSAA 2024 — other branches close at considerably higher ranks.

InstituteLocationTypeCSE closing rank · JoSAA '24
NIT Tiruchirappalli (Trichy)Tamil NaduNIT≈ 1,224
NIT Karnataka, SurathkalKarnatakaNIT≈ 1,615
NIT WarangalTelanganaNIT≈ 2,186
MNNIT AllahabadUttar PradeshNIT≈ 5,500
NIT RourkelaOdishaNIT≈ 6,500
VNIT NagpurMaharashtraNIT≈ 6,800
MNIT JaipurRajasthanNIT≈ 7,500
NIT CalicutKeralaNIT≈ 8,500
SVNIT SuratGujaratNIT≈ 9,000
IIIT AllahabadUttar PradeshIIIT≈ 9,500
NIT DelhiDelhiNIT≈ 12,000
IIIT Gwalior (ABV-IIITM)Madhya PradeshIIIT≈ 14,000

A representative set of institutes that admit through JEE Main. Many more engineering institutes participate in the counselling process.

JEE Main important dates

The typical JEE Main timeline, from notification to counselling. Dates are tentative until the official notification is released.

  1. JEE Main 2026 Session 1 exam

    21 – 30 January 2026

  2. Session 1 result

    12 February 2026

  3. JEE Main 2026 Session 2 exam

    2 – 8 April 2026

  4. Session 2 result & final All India Rank

    20 April 2026

  5. JEE Advanced 2026

    17 May 2026

  6. JoSAA 2026 counselling

    June 2026 onwards

JEE Main — frequently asked questions

Quick, reliable answers to the questions JEE Main aspirants ask most.

What is the JEE Main exam pattern and marking scheme?

JEE Main Paper 1 has three subjects — Physics, Chemistry and Mathematics. Each subject shows 20 multiple-choice questions and 10 numerical-value questions, of which you attempt any 5, so you answer 75 questions in all for 300 marks. Both question types award +4 for a correct answer and −1 for an incorrect one, and there is no penalty for unattempted questions.

How many times can I attempt JEE Main?

You can attempt JEE Main in three consecutive years. Both sessions (usually January and April) held within the same year together count as a single attempt, and only your best NTA score across the two sessions is used for ranking.

What is the difference between JEE Main and JEE Advanced?

JEE Main is the first stage, used for admission to the NITs, IIITs and GFTIs. The roughly top 2.5 lakh JEE Main rankers become eligible for JEE Advanced, which is the separate, tougher exam used exclusively for admission to the IITs.

Is 75% in Class 12 compulsory for JEE Main?

You can appear for JEE Main regardless of your Class 12 marks, but to be admitted to an NIT, IIIT or GFTI through JoSAA you must have scored at least 75% in Class 12 (65% for SC/ST candidates) or be within the top 20 percentile of your qualifying board.

How is the JEE Main percentile and rank calculated?

Because the exam runs across many shifts, NTA normalises raw marks into a percentile score for each session. Your percentile reflects the proportion of candidates you scored better than, and the All India Rank is compiled from the best of your two session percentiles. A 100 percentile corresponds to All India Rank 1.

Which colleges can I get with a JEE Main rank?

A JEE Main rank is used for admission to the 31 NITs, the IIITs and the GFTIs through JoSAA and CSAB counselling, and is also accepted by numerous state government and private engineering colleges. IIT admission, however, requires clearing JEE Advanced.

Official sources & references

The JEE Main pattern, marking, eligibility and dates on this page are verified against National Testing Agency (NTA). Exam details can change each cycle — always confirm current specifics on the official source before you rely on them.

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